- Period 1 has two elements H
and He. It involves the filling up of main energy level n = 1 which
consists of only a 1s orbital.
- Period 2 has 8 elements Li-Ne.
It involves the filling up of main energy level n = 2 which consists
of two sub-shells 2s and 2p.
- Period 3 has 8 elements Na-Ar. It involves the filling up of sub-shells 3s and 3p.
Wait a minute. The main energy level n = 3 has three sub-shells 3s, 3p and 3d, not just two. Why is the 3d sub-shell not filled up in Period 3 so that we get 18 elements instead of only 8? This is because the 4s orbital is lower in energy than the 3d orbitals. After the 3p sub-shell is filled in Ar, the next electron goes to 4s. This filling up of 4s leads us to the s-block elements K and Ca in Period 4.
Period
1 to Period 3: Filling up of 1s (Period 1) --> 2s2p (Period 2) -->
3s3p (Period 3)
In O Level, we learned very little about transition metals. All we know are that, unlike Groups I and II metals, they have variable oxidation states (e.g. Fe2+ and Fe3+), form coloured compounds (e.g. CuSO4.5H2O(s) is blue, KMnO4(aq) is purple), are dense (e.g. Density of iron = 7.86 g/cm3) and are catalysts of reactions (e.g. Fe used in the Haber Process).
These 10 elements in Period 4 correspond to the filling up of the 3d orbitals. From Sc to Zn, the electronic configuration changes from [Ar]4s23d1 to [Ar]4s23d10.
Period
4: Filling up of 4s (in s-block: K, Ca) --> 3d (in d-block: Sc-Zn)
--> 4p (in p-block: Ga-Kr)
The pattern, however, is not neat. It's broken at the 4th element Cr and 9th element Cu. Instead of [Ar]4s23d4, Cr has [Ar]4s13d5 and instead of [Ar]4s23d9, Cu has [Ar]4s13d10. There's no short explanations for why these happen. Just take them as they are.
Now, what're transitions elements? Most syllabi define a transition metal as one which forms at least one stable ion with partially filled d orbitals. Manganese, iron and copper are examples of transition metals because they form Mn2+ (3d5), Fe3+ (3d5) and Cu2+ (3d9) with incomplete d sub-shell. Scandium and zinc, however, aren't considered transition metals because they form Sc3+ (3d0) and Zn2+ (3d10) which don't have partially filled d sub-shell.
Not
all d-block elements are transition metals...
Try these questions before you check with the answers below.
- Complete the table that shows the electronic configurations of elements in the first row of the d-block. Scandium has been done for you.
- Write down the oxidation state
of manganese in Mn2+, Mn2O3, MnO2,
MnO42- and MnO4-.
- Write down some of the formulas of the ions formed by the first row of the d-block elements and the number of electrons in their 3d shell. For example, Sc3+ (d0).
4s
|
3d
|
||||||||
Sc
|
[Ar]
|
↑↓
|
↑
|
||||||
Ti
|
[Ar]
|
↑↓
|
↑
|
↑
|
|||||
V
|
[Ar]
|
↑↓
|
↑
|
↑
|
↑
|
||||
Cr
|
[Ar]
|
↑
|
↑
|
↑
|
↑
|
↑
|
↑
|
||
Mn
|
[Ar]
|
↑↓
|
↑
|
↑
|
↑
|
↑
|
↑
|
||
Fe
|
[Ar]
|
↑↓
|
↑↓
|
↑
|
↑
|
↑
|
↑
|
||
Co
|
[Ar]
|
↑↓
|
↑↓
|
↑↓
|
↑
|
↑
|
↑
|
||
Ni
|
[Ar]
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
↑
|
↑
|
||
Cu
|
[Ar]
|
↑
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
||
Zn
|
[Ar]
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
- Which elements in the first row of d-block are transition metals? Why?
Answers: 1.
4s
|
3d
|
||||||||
Sc
|
[Ar]
|
↑↓
|
↑
|
||||||
Ti
|
[Ar]
|
↑↓
|
↑
|
↑
|
|||||
V
|
[Ar]
|
↑↓
|
↑
|
↑
|
↑
|
||||
Cr
|
[Ar]
|
↑
|
↑
|
↑
|
↑
|
↑
|
↑
|
||
Mn
|
[Ar]
|
↑↓
|
↑
|
↑
|
↑
|
↑
|
↑
|
||
Fe
|
[Ar]
|
↑↓
|
↑↓
|
↑
|
↑
|
↑
|
↑
|
||
Co
|
[Ar]
|
↑↓
|
↑↓
|
↑↓
|
↑
|
↑
|
↑
|
||
Ni
|
[Ar]
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
↑
|
↑
|
||
Cu
|
[Ar]
|
↑
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
||
Zn
|
[Ar]
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
↑↓
|
2. Oxidation states: Mn2+ (+2), Mn2O3 (+3), MnO2 (+4), MnO42- (+6) and MnO4- (+7). 3. Ti: +3 (d1), +4 (d0). V: +2 (d3), +3 (d2), +4 (d1), +5 (d0). Cr: +3 (d3), +6 (d0). Mn: +2 (d5), +3 (d4), +4 (d3), +6 (d1), +7 (d0). Fe: +2 (d6), +3 (d5). Co: +2 (d7), +3 (d6). Ni: +2 (d8). Cu: +1 (d10), +2 (d9). Zn: +2 only (d10). 4. Titanium, vanadium, chromium, manganese, iron, cobalt, nickel and copper are transition metals because they form ions with incomplete d sub-shell.
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