Not all salt
solutions are neutral...
How do you predict whether a salt solution is acidic, neutral or alkaline? Recall from your Chemistry course that a salt is formed from an acid and a base. Begin from this and decide whether the base and acid are strong or whether they dissociate completely.
Let's begin from HA
+ BOH --> BA + H2O...
Then decide if acid
HA and alkali BOH are strong...
Acidic salt | Neutral salt | Alkaline salt |
Aluminium chloride
3HCl(aq) + Al(OH)3(s) = AlCl3(aq) + 3H2O(l) HCl(aq) is a strong acid: HCl(aq) --> H+(aq) + Cl-(aq) We know that Al(OH)3(s) is a weak alkali because it is an insoluble ppt: Al(OH)3(s) = Al3+(aq) + 3OH-(aq) |
Potassium nitrate
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Both nitric acid and potassium bromide are strong. |
Sodium bicarbonate
H2CO3(aq) + NaOH(aq) = Na2CO3(aq) + 2H2O(l) H2CO3(aq) is a weak acid: H2CO3(aq) = 2H+(aq) + CO32-(aq) NaOH(aq) is a strong alkali: NaOH(aq) --> Na+(aq) + OH-(aq) |
Zinc sulfate
H2SO4(aq) + Zn(OH)2(s) = ZnSO(aq) + H2O(l) H2SO4(aq) is a strong acid: H2SO4(aq) --> 2H+(aq) + SO42-(aq) We know that Zn(OH)2(s) is a weak alkali because it is an insoluble ppt: Zn(OH)2(s) = Zn2+(aq) + 2OH-(aq) |
Calcium bromide
2HBr(aq) + Ca(OH)2(aq) --> CaBr2(aq) + 2H2O(l) Both HBr(aq) and Ca(OH)2(aq) are strong. |
Rubidium fluoride
HF(aq) + RbOH(aq) = RbF(aq) + H2O(l) HF is a weak acid: HF(aq) = H+(aq) + F-(aq) RbOH(aq) is a strong alkali: RbOH(aq) --> Rb+(aq) + OH-(aq) |
Ammonium chloride
HCl(aq) + NH3(aq) = NH4Cl(s) HCl(aq) is a strong acid: HCl(aq) --> H+(aq) + Cl-(aq) NH3(aq) is a weak alkali: NH3(aq) + H2O(l) --> NH4+(aq) + OH-(aq) |
Sodium ethanoate (sodium acetate)
CH3COOH(aq) + NaOH(aq) = CH3COONa(aq) + H2O(aq) CH3COOH(aq) is a weak acid: CH3COOH(aq) = CH3COO-(aq) + H+(aq) NaOH(aq) is a strong alkali. |
Try these questions before you check with the answers below.
- Predict whether iron(III) chloride is acid, neutral or
alkaline. Explain your answer.
- Explain why (a) barium nitrate (b) sodium sulfate solutions
are neutral.
Answers: 1. 3HCl(aq) + Fe(OH)3(s) = FeCl3(aq) + 3H2O(l). HCl(aq) is a strong acid. We know that Fe(OH)3(s) is a weak base because it is an insoluble ppt. Therefore, FeCl3(aq) is an acidic salt solution. 2. (a) 2HNO3(aq) + Ba(OH)2(aq) --> Ba(NO3)2(aq) + H2O(l). Both HNO3(aq) and Ba(OH)2(aq) are strong. (b) H2SO4(aq) + NaOH(aq) --> Na2SO4(aq) + H2O(l). Both H2SO4(aq) and NaOH(aq) are strong.
No comments:
Post a Comment